Mathematics, 16.01.2020 04:31 Lizae9099

Hey‼️‼️ can someone with this⁉️ 1 and 4 are completed i need 2 3 5 6 7 8 9 use the formula sa= ph + 2b b= base p= perimeter

Hey‼️‼️ can someone with this⁉️ 1 and 4 are completed i need 2 3 5 6 7 8 9 use the formula sa= ph +

Answers: 2

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Answers

Answer from: poop2351

Part 1) $SA=58\ cm^2$

Part 2) $SA=90\ ft^2$

Part 3) $SA=168\ m^2$

Part 4) $SA=96\ in^2$

Part 5) $SA=660\ in^2$

Part 6) $SA=96\ cm^2$

Part 7) Your friend is not correct, $SA=150\ cm^2$

Part 8) $SA=486\ in^3$

Part 9) $SA=94\ ft^2$

Step-by-step explanation:

we know that

The surface area of a rectangular prism is equal to

SA=2B+Ph

where

B is the area of the base of the prism

P is the perimeter of the base of the prism

h is the height of the prism

Part 1) Find the surface area of the rectangular prism

Find the area of the base B

$B=(4)(1)=4\ cm^2$

Find the perimeter of the base

$P=2(4+1)=10\ cm$

we have

$h=5\ cm$

substitute the values in the formula of surface area

$SA=2(4)+10(5)=58\ cm^2$

Part 2) Find the surface area of the rectangular prism

Find the area of the base B

$B=(2)(5)=10\ ft^2$

Find the perimeter of the base

$P=2(2+5)=14\ ft$

we have

$h=5\ ft$

substitute the values in the formula of surface area

$SA=2(10)+14(5)=90\ ft^2$

Part 3) Find the surface area of the rectangular prism

Find the area of the base B

$B=(9)(6)=54\ m^2$

Find the perimeter of the base

$P=2(9+6)=30\ m$

we have

$h=2\ m$

substitute the values in the formula of surface area

$SA=2(54)+30(2)=168\ m^2$

Part 4) Find the surface area of the triangular prism

Find the area of the triangular base B

$B=(1/2)(8)(3)=12\ in^2$ ---> the area of triangle

Find the perimeter of the triangular base

$P=8+5+5=18\ in$

we have

$h=4\ in$

substitute the values in the formula of surface area

$SA=2(12)+18(4)=96\ in^2$

Part 5) Find the surface area of the triangular prism

Find the area of the triangular base B

$B=(1/2)(12)(5)=30\ in^2$ ---> the area of triangle

Find the perimeter of the triangular base

$P=12+5+13=30\ in$

we have

$h=20\ in$

substitute the values in the formula of surface area

$SA=2(30)+30(20)=660\ in^2$

Part 6) Find the surface area of the triangular prism

Find the area of the triangular base B

$B=(1/2)(6)(8)=24\ cm^2$ ---> the area of triangle

Find the perimeter of the triangular base

$P=8+6+10=24\ cm$

we have

$h=2\ cm$

substitute the values in the formula of surface area

$SA=2(24)+24(2)=96\ cm^2$

Part 7) we know that

The surface area of a cube is equal to the area of its six square faces

SA=6b^2

where

b is the length side of the cube

we have

$b=5\ cm$

substitute

SA=6(5^2)

$SA=150\ cm^2$

therefore

Your friend is not correct

The surface area of the cube is $SA=150\ cm^2$

Part 8) we know that

The surface area of a cube is equal to the area of its six square faces

SA=6b^2

where

b is the length side of the cube

we have

$b=9\ in$

substitute

SA=6(9^2)

$SA=486\ in^3$

Part 9) Find the surface area of the rectangular prism (shipping crate)

Find the area of the base B

$B=(5)(4)=20\ ft^2$

Find the perimeter of the base

$P=2(5+4)=18\ ft$

we have

$h=3\ ft$

substitute the values in the formula of surface area

$SA=2(20)+18(3)=94\ ft^2$

Answer from: Quest

Answer d; a supplementary angle = 180°, so if that angle = 150°, y would = 30°.
In the diagram below, ab is parallel to cd. what is the value y? a.150b.50c.60d.30

Answer from: Quest

answer are

step-by-step explanation:

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