Iwant to know which of two manufacturing methods will be better. i create 10 prototypes using the first process and 10 using the second. there were three defectives in the first batch and five in the second. what is a 95% confidence interval for the difference in the proportion of defectives?

(-0.620, 0.220)

Step-by-step explanation:

The formula to find the confidence interval for the difference in true proportion of the two groups. is given by :-

, where = Sample size for first group.

= Sample size for second group.

= Sample proportion for first group.

= Sample proportion for second group.

z* = critical z-value.

Let first group be "group of prototypes by first process " and second group be "group of prototypes by second process".

= Proportion of defectives in the first batch.

= Proportion of defectives in the second batch.

From question , we have

,  ,  ,

By z-table , Critical value for 95% confidence interval is z* =1.96.

Substitute all values in formula , we get

Hence,  a 95% confidence interval for the difference in the proportion of defectives is (-0.620, 0.220).

step-by-step explanation:

let

we know that

the y-intercept is the y-coordinate of the point when the value of x is equal to zero

so

the y-coordinate of the point a is the y-intercept

the answer part a) is

the value of y-intercept is

part b) find the slope m

we know that

the value of the slope is equal to

substitute the values

therefore

the answer part b) is

the value of the slope is equal to

the general answer is

the slope is

the value of y-intercept is