Parallelogram defg is transformed to parallelogram vstu.

parallelogram d e f g is reflected diagonally to form parallelogram v s t u.

which statement about the transformation is true?

Ok. I seem to have to say this a lot, but It is hard to answer a question about a graph, if it doesn't come with a graph to answer it with. So next time, please include a picture or a small screenshot of the graph in your question. Thank you.

The answer is option A

Step-by-step explanation:

Since the original figure is DEFG, therefore DEFG is preimage and VSTU is the image because it is the result of the transformation.

So the option A is correct, or

"Parallelogram DEFG is the pre-image because it is not the result of the transformation".

Also, this is the graph you are looking for(down below)

360 different combinations

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3