At a school, 43% of students attend the homecoming football game. only 23% of students go to the game and the homecoming dance. what is the probability that a student who attends the football game also attends the dance?

0.535

Step-by-step explanation:

Let students that attend homecoming = H

Let students that attend football game = F

Pr(H) = 43% = 0.43

Pr (H and F) = 23% = 0.23

For conditional probability,

Pr(H and F) = Pr(H) * Pr(H|F)

Pr(H|F) = Pr(H and F) / Pr(H)

=0.23/0.43

Pr(H|F) = 0.535

The probability that a student attends football game and also attends dance = 0.535

step-by-step explanation: 4 cause 2+2=4