Find the slope of the line that passes through (6,10) and (1,1)

X2 =5

Y2 =4

ΔX =4

ΔY =3

θ =36.869897645844°

Equation of the line:

y = 0.75x + 0.25

When x=0, y = 0.25

When y=0, x = -0.33333333333333

OR

X2 =-3

Y2 =-2

ΔX =-4

ΔY =-3

θ =216.86989764584°

Equation of the line:

y = 0.75x + 0.25

When x=0, y = 0.25

When y=0, x = -0.33333333333333

anser is a

step-by-step explanation:

negitive slope