Seth is using the figure shown below to prove pythagorean theorem using triangle similarity:

in the given triangle abc, angle a is 90o and segment ad is perpendicular to segment bc.

the figure shows triangle abc with right angle at a and segment ad. point d is on side bc.

which of these could be a step to prove that bc2 = ab2 + ac2?
a

by the cross product property, ab2 = bc multiplied by bd.
b

by the cross product property, ac2 = bc multiplied by bd.
c

by the cross product property, ac2 = bc multiplied by ad.
d

by the cross product property, ab2 = bc multiplied by ad.

what is the original number? you forgot to add it.

v,jhvljh,b.b; hk; ljujb,vuvccklokll; k,m,km,

step-by-step explanation:

step-by-step explanation:

i'm pretty sure it would take 20 hours because it's half the men so you multiply the number of hours it takes by 2

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.