Using substitution to solve a linear system

y=9-x
and
2x+3y=11

how would i solve this?

x = 16

y = -7

Step-by-step explanation:

y = 9 - x

2x + 3y = 11

y = 9 - x

2x + 3(9 - x) = 11

y = 9 - x

2x + 27 - 3x =11

y = 9 - x

-x + 27 = 11

y = 9 - x

-x = - 16

y = 9 - 16

x = 16

y = -7

x = 16

there is only 1 solution for this equation is (16,-7)

72 fudge and 75 toffee

step-by-step explanation:

i hope this : )

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.