Given m∠2 = 80°, m∠1 = 4 · m∠3, and ∠4 ≅ ∠ 8, find m∠1, m∠3, m∠4, m∠5, m∠6, m∠7, and m∠8.

m∠1= m∠5= 100°, m∠2= m∠6= 80°, m∠4=m∠8= 155°, m∠3= m∠7= 25°

Step-by-step explanation:

Supposing ∠1,∠2  make up a straight angle.Let ∠1, ∠5 and ∠2 and ∠6 be corresponding angles on a transversal  drawn on two  parallel lines. ∠3,∠4 and∠5 ∠6  be interior angles

If m ∠= 80° them m∠ 1= 100°

As ∠1= 4. m∠3 therefore

100°= 4.m∠3

m∠3= 100/4= 25°

Again supposing m∠3+ m∠4= 180°

m∠4= 180°- 25°= 155°

m∠4 =m∠8= 155°

m∠8 + m∠7= 180°

m∠7= 180°- 155°= 25°

Let  ∠5 and ∠1 be corresponding angles so m∠5= m∠1= 100°

and m∠6= m∠2= 80°

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

a framing bias

step-by-step explanation:

rodrigo is subject to a framing bias i believe.