The remainder when p\left(x\right)=x^3-2x^2+8x+kp ( x ) = x 3 − 2 x 2 + 8 x + k by (x-2) is 19. what is the remainder when p(x) is divided by (x+2)?

Remainder when p(x) is divided by (x+2) is -29

Step-by-step explanation:

p(x) =

When p(x) is divided by (x-2), remainder is 19.

p(x - 2 = 0)  gives the remainder when p(x) is divided by (x-2)

x - 2 = 0

x = 2

p(x-2=0) = p(2) = = 19

8 - 8 + 16 + k = 19

k = 3

p(x) =

p(x + 2 = 0)  gives the remainder when p(x) is divided by (x+2)

x + 2 = 0

x = -2

p(x+2=0) = p(-2) =

p(-2) = - 8 - 8 - 16 + 3 = -29

Remainder when p(x) is divided by (x+2) is -29

✩ Given Polynomial : x³ - 2x² + 8x + k

when p(x) is divided by (x - 2) it gives 19 as remainder. HENCE WE CAN SAY.

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f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

yes because there is exactly one y value for every x value

for function there can't be more than one value for every x value