H(t)=(t+3)^2+5

what is the average rate of change of h over the interval −5≤t≤−1?

The average rate of change is 0

Solution:

The average rate of change of function is given as:

Here the given function is:

The interval given is

The average rate of change of the function h(t) over the interval can be calculated as:

Find h( -5 ) and h( -1 ):

Substitute t = -5 in given h(t)

Substitute t = -1 in given h(t)

Thus average rate of change is given as:

Thus the average rate of change is 0

the image of (6, 9) under a dilation is (4, 6). the scale factor is

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing im pretty sure that is the right answer

step-by-step explanation: