Itook a sample of the grade point averages for students in my class. for 25 students, the standard deviation of grade points was 0.65 and the mean was 2.89. a 95% confidence interval for the average grade point average for all students in my class is:

a. (2.64, 3.14).
c. (2.53, 3.25).
b. (2.62, 3.16).

B. (2.62, 3.16)

Step-by-step explanation:

Confidence Interval = mean + or - (t×sd)/√n

Mean = 2.89, sd = 0.65, n = 25, degree of freedom = n-1 = 25-1 = 24, t-value corresponding to 24 degrees of freedom and 95% confidence level is 2.064

Lower limit = 2.89 - (2.064×0.65)/√25 = 2.89 - 0.27 = 2.62

Upper limit = 2.89 + (2.064×0.65)/√25 = 2.89 + 0.27= 3.16

95% confidence interval is (2.62, 3.16)

answer: idk wbu

step-by-step explanation: