Karen amad an hans have a total of 113 in their wallets? if hans has 4 times the amount of karen an karen has 7 dollars more than amad, how much is in each wallet

Amount in Han wallet = $ 80

Amount in amad wallet = $ 13

Amount in karen wallet = $ 20

Solution:

Let "h" be the amount in Han's wallet

Let "k" be the amount in karen wallet

Let "a" be the amount in amad wallet

They have a total of 113 in their wallet

Therefore,

h + k +a = 113 eqn 1

If hans has 4 times the amount of karen

Amount with Han = 4 times the amount with Karen

h = 4k eqn 2

And karen has 7 dollars more than amad

k = 7 + a

a = k - 7 eqn 3

Substitute eqn 2 and eqn 3 in eqn 1

4k + k + k - 7 = 113

6k - 7 = 113

6k = 113 + 7

6k = 120

k = 20

Substitute k = 20 in eqn 3

a = 20 - 7

a = 13

Substitute k = 20 in eqn 2

h = 4k = 4(20) = 80

h = 80

Summarizing the results:

Amount in Han wallet = $ 80

Amount in amad wallet = $ 13

Amount in karen wallet = $ 20

1. sometimes

2. never true

3. sometimes

step-by-step explanation:

these are pretty self explanatory if you know what supp right and com angles are

i think it might be a but you might want a second opinion