Four students can choose to participate in a charity event either on saturday or sunday. what’s the probability that there is at least one student at both saturday's and sunday's events? a) 1/8b) 3/8c) 5/8d) 7/8

D) 7/8

Step-by-step explanation:

The probability that there is at least one student at both Saturday's and Sunday's events is the inverse of the probability of having all students selecting either Saturday OR Sunday.

Since the probability of a student selecting Saturday is 0.5, the probability of all 4 students selecting that day is

0.5 * 0.5 * 0.5 * 0.5 = 1/16

Then the probability of having all students selecting either Saturday OR Sunday is twice that, which is 2/16, or 1/8

Therefore the probability that there is at least one student at both Saturday's and Sunday's events is 1 - 1/8 = 8/8 - 1/8 = 7/8

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

were is the equation