Motion and rate of change derivatives. attached is the question and where i am stuck, i would really appreciate the : )

  A.  3 < t < 9

Step-by-step explanation:

You have successfully found the values of t where the motion turns around (t=3 and t=10). Your knowledge of odd-degree polynomials tells you that the value of s(t) is decreasing for t < 3 (because the leading coefficient is negative), and is also decreasing for t > 10.

That is, the value of s(t) is increasing between t=3 and t=10, which means the particle is moving to the right in that interval. Since the function is only defined on the interval [0, 9] the particle is moving to the right on the interval (3, 9).

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At t=3 and t=10, the particle is stationary, moving neither right nor left.

don't report but were is the digram

step-by-step explanation: