Fred begins walking toward johns house at 3 miles per hour. john leaves his house at the same time and walks towards fred’s house on the same path at a rate of 2 miles per hour. how long will it take before they meet if their houses are 4 miles apart?

It takes hours or 48 minutes before they meet if their houses are 4 miles apart

Solution:

Let "t" be the number of hours it will take them to meet

Walking speed of Fred = 3 miles per hour

Walking speed of John = 2 miles per hour

Distance between their house = 4 miles

Distance is given by formula:

Distance = speed x time

Fred distance = walking speed of Fred x time taken

Fred distance = 3t

John distance = walking speed of John x time taken

John distance = 2t

Therefore,

3t + 2t = 4

5t = 4

hours

We know that,

1 hour = 60 minutes

Therefore,

Thus it takes hours or 48 minutes before they meet

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.

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