Arectangle parking lot has a lake that is 5 yards greater than the width. the area of the parking lot is 500 square yards. find the length and the width

Width = 20 yards

Length = 25 yards

We are given;

We are going to take;

But the area of a rectangle = length × width

Therefore;

x × (x +5) = 500

x² + 5x = 500

Rearranging in quadratic manner

x² + 5x - 500 = 0

Solving the quadratic equation;

Using factorization method

(x+25)(x-20) = 0

Therefore;

x = 20 or -25

We take, x = 20

Thus;

Width = 20 yards

Length = 25 yards

24

step-by-step explanation:

step-by-step explanation: i dont