Can you me with this side of these problems.

6: Reason 2 - substitution, Statement 4 - PR congruent to PR, Reason 4 - reflexive property, Reason 5 - AAS

8: Rotation

Step-by-step explanation:

6: Since both of the given angles equal 90°, you can substitute Angle RPT in to make Angle PRQ congruent to Angle RPT. Then, since both triangles share Line PR, PR would be congruent to PR by the reflexive property. And since you know that Angle Q is congruent to Angle T, you can see that Triangle QRP is congruent to Triangle TPR by the AAS theorem.

8: Since the 1st triangle is pointing to the right and the 2nd triangle is pointing downward, this would be a rotation of 90° clockwise (or 90° counterclockwise if the 1st triangle is the one pointing downward)

I don't have 7, sorry.

Also (if you haven't noticed it already), there's a typo in the 1st statement of the proof. Just thought I'd let you know ;)

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2