Jaime has 5 over 11 spaceof a project completed while tim has finished 7 over 13 spaceof the same project.

a. who has completed the greater amount of work?

b. how much of the project have they completed together? show your work.

Part a) Tim has completed the greater amount of work

Part b) They have completed together of the project or of the project

Step-by-step explanation:

Part a) Who has completed the greater amount of work?

we have

Jaime has 5/11 of a project completed

Tim has 7/13 of a project completed  

Multiply 5/11 by 13/13 and 7/13 by 11/11

so

Jaime --->

Tim --->

Remember that

When fractions have the same denominator, the larger fraction is the one with the larger numerator  

therefore

Tim has completed the greater amount of work

Part b)  How much of the project have they completed together?

we have that

Jaime has 65/143 of a project completed  

Tim has 77/143 of a project completed  

Sum the fraction of the project completed by Jaime plus the fraction of the project completed by Tim

Convert to percentage

Multiply by 100

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

the answer would be 44.79

plz mark brainliest

step-by-step explanation: