Given: ∆abc, ab = bc, m∠1< 90° perimeter of ∆abc = 25 difference between two sides is 4 find: ab, bc, ac

The value of is AB = BC = unit , AC is unit  .

Step-by-step explanation:

Given as :

In a triangle ABC ,

Let The three sides be AB , BC , CA

Side AB = Side BC , ∠B = 90°

Perimeter of ΔABC =25 unit

Or, AB + BC + CA = 25 unit  

Or, AB + AB + CA = 25 unit

i.e 2 AB + CA = 25 unit                    .....1

And Difference between two sides = 4

So, AB - CA = 4 unit                        .......2

Now, According to question

From eq 1 and eq 2

(2 AB + CA) + (AB - CA) = 25 unit + 4 unit

Or, (2 AB + AB) + (CA - CA) = 29

Or, 3 AB + 0 = 29

∴ AB = unit

∵ BC = AB

So, BC = unit

Again

∵ AB - CA = 4 unit

So, AC = AB - 4

Or, AC = unit - 4 unit

Or, AC = unit

i.e AC =   unit

So, The value AB = BC = unit , AC = unit

Hence, The value of is AB = BC = unit , AC is unit  . Answer

a) 7x=7

step-by-step explanation:

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.