Mathematics, 12.01.2020 00:31 xelynncaldera
Which hyperbolas have one vertex in common with the hyperbola (y-4)^2/7^2 - (x+6)^2/8^2=1? ! urgent
a. (y-8^2/5^2 - (x+6)^2/6^2=1
b. (x-1)^2/8^2 - (y-11)^2/7^2=1
c. (x+15)^2/9^2 - (y+3)^2/5^2=1
d.(y-6)^2/6^2- (x+6)^2/4^2=1
e. (y-23)^2/12^2 - (x+6)^2/8^2=1
Answers: 3
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Which hyperbolas have one vertex in common with the hyperbola (y-4)^2/7^2 - (x+6)^2/8^2=1? ! urge...
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