How many of the 9 people listed in the scatterplot have an actual height that differs by more than 3 centimeters from the height predicted by the line of best fit?

So as we can see we have 4 points out of the 9 who satisfy the condition

Step-by-step explanation:

We assume that we have a plot given like the figure 1 attached

We have n points and we need to find How many of the 9 people listed in the scatterplot have an actual height that differs by more than 3 centimeters from the height predicted by the line of best fit?

So for this case we need to have the predicted value and the real value y. We are going to put these two values and the difference

     157                      161.5                        4.5

     163                      163.1                        0.1

     175                      167                           8.0

     171                       170.5                        0.5

     173                      172.5                        0.5

     173                      174.3                        1.3

     172                      176                           4.0

     183                      178                           5.0

     178                      180                           2.0

So as we can see we have 4 points out of the 9 who satisfy the condition

33

step-by-step explanation: g=6

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3