Find the standard form of the equation of the parabola with the given characteristics

Step-by-step explanation:

The standard equation of a parabola is

y² = 4ax

where, a is the focus,

The coordinates of the centre of parabola is (0,0)

coordinates of focus is (a, 0)

It is symmteric about the x axis

the equation of directrix is x = -a.

-10i^2-4i

step-by-step explanation:

evaluate for p=2,q=5i

(2−4)(2+5i)i

(2−4)(2+5i)i

=−10i2−4i

range =5

step-by-step explanation:

to find the range, we take the largest value and subtract the smallest value.

the largest value is 5

the smallest value is 0

the range is 5-0   =5