A60-watt light bulb uses 60 watt hours of electricity in 1 hour. suppose everyone in the united states lef one unneeded 60 watt light bulb on for one hour everyday for a year.

electricity is billed in kilowatt hours. so 60 watt hours is equal to sixty divided by one thousand. express the electricity used by a 60 watt light bulb in one hour in kilowatt hours in scientific notation.

kilowatt-hours.

Step-by-step explanation:

If a 60-watt light bulb is used every day for one year, then this will consume (365 × 60) = 21900 watt-hours of electricity.

{Because one complete year consists of 365 days}

This 21900 watt-hour is equivalent to kilowatt-hours.

Therefore, in scientific notation the electricity consumed by each bulb in kilowatt-hour is . (Answer)

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}