Of the three digit integers greater than 700, how many have two digits that are equal to each other and the remaining digit different from the other two?
a) 90
b) 82
c) 80
d) 45
e) 36

80.

Step-by-step explanation:

Three digit number can only have three patterns

A. All digits are distinct

B. Two digits are same and third is different

C. All three digits are alike.

We need to calculate B

that is B= Total- A-C

Total numbers from 700 to 999= 299.

Number numbers having all digits distinct = 3×9×8= 216 ( first digit can have only three digits 7,8,9)

All three are alike = 3 ( 777,888,999).

So, 299 -216-3= 80.

the solution is the point

step-by-step explanation:

we have

> equation a

> equation b

adds equation a and equation b

substitute the value of x in equation b to find the value of y

the solution is the point

e

step-by-step explanation:

an equation by definition has to have two or more variables (x and 2 in this case)