Find an equation for the line through the point p = (1, 0, −3) and perpendicular to the xy-plane.

Step-by-step explanation:

given that a line is perpendicular to xy plane.

Also the line passes through (1,0,-3)

In three dimension rectangular coordinates we have 3 mututally perpendicular lines as three axes.

Here since the given line is perpendicular to xy plane, and equation of xy plane is z=0 we find that the required line has direction ratios as (0,0,1)

(since 0.x+0.y+1.z=0 is the plane equation normal has (0.0,1)

It passes through (1,0,-3)

So in parametrical form we write equation as

$12. that is my answer.

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