F(x) = -12x + 48
what is the zero of the following linear function?

x = 4

Step-by-step explanation:

To find the zero, let f(x) = 0, that is

- 12x + 48 = 0 ( subtract 48 from both sides )

- 12x = - 48 ( divide both sides by - 12 )

x = 4

4

Step-by-step explanation:

The zero of a function is the value of the unknown at which the function is zero.

f(x) = -12x + 48

we will equate f(x) to zero , that is

0 = - 12x + 48

12x = 48

divide through by 12

x = 4

Check: let us substitute x = 4 into the function

f(x) = -12(4) + 48

f(x) = -48 + 48

f(x) = 0

Therefore, 4 is the zero of the linear function

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

step-by-step explanation:

what are the statements? and what do you mean by "216 2 1 6"?