By how many units is the interquartile range for orlando's data set greater than the interquartile range for victor's data set? victor's data set: {22, 29, 32, 27, 30} orlando's data set: {36, 25, 33, 27, 35}

By 3 units is the interquartile range for Orlando's data set greater than the interquartile range for Victor's data set.

Step-by-step explanation:

Given:

Victor's Data Set: {22, 29, 32, 27, 30}.

Orlando's Data Set: {36, 25, 33, 27, 35}.

Now, to find the units is the interquartile range for Orlando's data set greater than the interquartile range for Victor's data set.

So, we get the interquartile range of Victor's Data Set:

{22,27,29,30,32}

Q3 =

Q3 =

Q1 =

Q1 =

Thus, interquartile range is:

Interquartile range =

Interquartile range =

The interquartile range of Victor's Data Set = 6.5.

Now, to get the interquartile range of Orlando's Data Set:

{25,27,33,35,36}

Q1 =

Q3 =

Thus, interquartile range is:

Interquartile range =

Interquartile range =

The interquartile range of Orlando's Data set = 9.5.

Now, to get the units of the interquartile range for Orlando's data set greater than the interquartile range for Victor's data set we subtract Victor's interquartile range from Orlando's interquartile range:

Therefore, by 3 units is the interquartile range for Orlando's data set greater than the interquartile range for Victor's data set.

college

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )