Each flower has a specific price. one tulip, one daisy, and 2 mums cost $4.20. on tulip, two daisies and one mum cost $3.80. two tulips and 2 mums cost $4.80. how much does one tulip, three daisies and 2 mums cost?

The answer to your question is $5.60

Step-by-step explanation:

    1 tulip + 1 daisy + 2 mums = $4.20           (1)

    1 tulip + 2 daisies + 1 mum = $ 3.80         (2)

    2 tulips + 2 mums = $4.80                        (3)

    1 tulip + 3 daisies + 2 mums = ?

tulip = t      daisy = d      mum = m

Process

1.- Find the price of each flower using system of equations

    Solve equation 3 for tulip

     2t = 4.80 - 2 m     divide by 2                            (4)

     t = 2.40 - 1m

2.- Substitute equation 4 in equation 1 and 2

    (2.4 - 1m) + 1 d + 2 m = 4.2

    (2.4 - 1m) + 2d + 1 m = 3.8

3.- Simplify and solve for each flower

     2.4 - 1m + 1d + 2m = 4.2

      1d + 1m = 4.2 - 2.4

      1d + 1m = 1.8                   Equation (5)

     2.4 - 1m + 2d + 1m = 3.8

     2d = 3.8 - 2.4

     2d = 1.4

     d = 1.4/2

     1d = 0.7

4.-  Substitue d in equation 5

     1(0.7) + 1m = 1.8

     0.7 + 1m = 1.8

     1m = 1.8 - 0.7

      1m = 1.1

5.- Subtitute m in equation 4

     1t = 2.40 - 1(1.1)

     1t = 2.40 - 1.1

      1t = 1.3

6.- Result

     1 tulip + 3 daisies + 2 mums cost = 1.3 + 3(0.7) + 2(1.1)

                                                            = 1.3 + 2.1 + 2.2

                                                            = $5.6

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.