Three consecutive integers are such that three times the smallest is 14 more than the largest

8, 9 and 10

Step-by-step explanation:

We would have to find the 3 consecutive integers.

Consecutive integers are one after another, such as:

1, 2, 3, ... etc.

So, if we let the first integer be "x", the next one is 1 unit apart, so next one would be:

x + 1

Next one:

x + 2

So, we have 3 consecutive integers:

x, x + 1, x + 2

It is given, 3 times smallest (x) is 14 MORE THAN largest (x + 2). So we can write:

3x = x + 2 + 14

Now we solve for x:

So, the integers are:

8, 9 and 10

answer:   b

step-by-step explanation:

x2 = 16

x can not be a negative number because 16 is positive

the only answer would be positive 8