Software that can be used to detect fraund in customer
phonecards, tracks the number of metropolitan areas from which
callsoriginate each day. suppose 1% of the legitimate users
originatecalls from two or more metropolitan areas in a single day;
and 30%of fradulent users originate calls from two or more
metropolitanarea in a single day. the overall proportion of
fraudulent users is0.01%. if the same person originates calls from
two or moremetropolitan areas in as ingle, what is probability that
such useis fraudlent?

0.002991

Step-by-step explanation:

Let

User is legitimate one = E₁

User is fraudulent one = E₂

User originates calls from two metropolitan = A

Therefore, according to the question

P(E₁) = 1 - 0.01% = 1 - 0.0001 = 0.9999

P(E₂) = 0.0001

P(A/E₁) = 1% = 0.01

P(A/E₂) = 30% = 0.30

Now,

P(E₂/A) =

or

P(E₂/A) =

or

P(E₂/A) = 0.002991

a

b

d

step-by-step explanation:

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.