Mathematics, 09.01.2020 01:31 dlshadowmorfe

8. suppose in a certain breed of dog, the color of fur can either be tan or black. eighty-five percent of the time, a puppy will be born with tan fur, while 15% of the time, the puppy will have
black fur. suppose in a future litter, six puppies will be born.
a. are the events having tan fur and having black fur independent? explain.
b. what is the probability that one puppy in the litter will have black fur and another puppy will have tan fur?
c. what is the probability that all six puppies will have tan fur?
d. is it likely for three out of the six puppies to be born with black fur? justify mathematically.

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a) On this case the two events are independent, because if one puppy is black the probability that the next one would be black or tan fur is not affected by the first outcome. On math terms we have this:

P(T|B) = P(T) = 0.85

P(B|T) =P(B) =0.15

b) On this case since the order no matter the probability would be:

P(B and T) = 0.15*0.85= 0.1275

And the two events are independent.

c) For this case the probability that all six puppies will have tan fur is:

P(6 Tan fur) = (0.85^6) = 0.377

d) On this case the probability that 3 puppies would be black fur means that the other 3 are tan fur. And the probability would be given by:

(0.15^3) (0.85^3) = 0.00207

So on this case is very unlikely since we have just about 0.2% of possibility.

Step-by-step explanation:

Notation

T= a pupy is tan fur, P(T) = 0.85

B= a puppy is black fur P(B) = 0.15

a. Are the events having tan fur and having black fur independent? Explain.

On this case the two events are independent, because if one puppy is black the probability that the next one would be black or tan fur is not affected by the first outcome. On math terms we have this:

P(T|B) = P(T) = 0.85

P(B|T) =P(B) =0.15

b. What is the probability that one puppy in the litter will have black fur and another puppy will have tan fur?

On this case since the order no matter the probability would be:

P(B and T) = 0.15*0.85= 0.1275

And the two events are independent.

c. What is the probability that all six puppies will have tan fur?

For this case the probability that all six puppies will have tan fur is:

P(6 Tan fur) = (0.85^6) = 0.377

d. Is it likely for three out of the six puppies to be born with black fur? Justify mathematically.

On this case the probability that 3 puppies would be black fur means that the other 3 are tan fur. And the probability would be given by:

(0.15^3) (0.85^3) = 0.00207

So on this case is very unlikely since we have just about 0.2% of possibility.

Answer from: Quest

Do the math. she originally had 50 dollars on her gift card and she had 12 dollars left on her gift card after she finished her shopping spree. if you subtract 50 minus 12 you get thirty eight dollars as your answer. so therefore, ciara spent 38 dollars total o

Answer from: Quest

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!

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8. suppose in a certain breed of dog, the color of fur can either be tan or black. eighty-five perce...

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