Answers: 2
.
is complete square if 
     ![[\because (a+b)^2=a^2+2ab+b^2]](/tpl/images/0447/5933/b93be.png)
 
:![a[x^2+\frac{1}{a}x+(\frac{1}{2a})^2-(\frac{1}{2a})^2]+3](/tpl/images/0447/5933/7d19d.png)
   ![a[x^2+\frac{1}{a}x+(\frac{1}{2a})^2-(\frac{1}{4a^2})]+3](/tpl/images/0447/5933/21ebd.png)
  
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Complete the square: ax^2 + x + 3....
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