Calculate the work associated with the expansion of a gas
from46l to64 l at
a constant external pressure of 15 atm?

-27 kJ

Step-by-step explanation:

Given data

We can find the work (w) associated with the expansion of a gas using the following expression.

w = - P . ΔV

w = - P . (Vf - Vi)

w = - 15 atm . (64 L - 46 L)

w = -270 atm.L . (101.325 J/ 1 atm.L)

w = -2.7 × 10⁴ J

w = -27 kJ

c

step-by-step explanation:

at least i think its

answer: the answer is (b) amie should have multiplied

step-by-step explanation: given a sphere and a cylinder with same radius and height.

let, 'r' be the radius of the cylinder and sphere and 'h' be the height of the cylinder. according to the question,

r = h.

now, the volume of the sphere will be

and the volume of the cylinder will be

therefore, we have

thus, ammie should have multiplied the volume of the sphere