In the triangle abc if angle a is 20 degrees, angle b is 35 degrees and the side between (side c) them is 100, what is the approximate length of side a?

length of side a is 42

Step-by-step explanation:

The given triangle ABC is shown in the attached photo. The length of side BC is a. The length of side AC is b and the length of side AB is c = 100

The sum of the angles in a triangle is 180 degrees. Therefore.

Angle A + angle B + angle C = 180. Therefore,

20 + 35 + angle C = 180

55 + angle C = 180

Angle C = 180 - 55 = 125 degrees. To determine the length if a, we would apply the sine rule which is expressed as

a/SinA = b/SinB = c/SinC

Therefore,

a/Sin20 = 100/Sin125

aSin125 = 100sin20

a × 0.8192 = 0.342 × 100

0.8192a = 34.2

a = 34.2/0.8192

a = 41.75

Approximately 42

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3