Let the velocity in miles per second of a particle in a particle accelerator after t seconds be modeled by the
function = tan ( / 6000 − / 2) on an unknown domain.
a. what is the t-value of the first vertical asymptote to the right of the y-axis?
b. if the particle accelerates to 99% of the speed of light before stopping, then what is the domain?
note: c ≈ 186000. round your solution to the ten-thousandths place.
c. how close does the domain get to the vertical asymptote of the function?
d. how long does it take for the particle to reach the velocity of earth around the sun (about 18.5 miles per
second)?
e. what does it imply that is negative up until t = 3000?

answer: no

step-by-step explanation:

you are only given the cost not the amount of pounds.

50x5=$250

step-by-step explanation:

let's cover over the formula of the vertex:

y = a(x – h)^2 + k

in this formula, (h,k) are the vertex, always remember that the positive or negative value of the vertex is based on the sign it has.

for example, if the vertex is -3,-6 then both the x and y value would have the positive sign attached to it and if it were a positive x and y value, then a negative sign would be attached to it.

with that being said, for our problem the x value is a positive one so we are looking for a number with a negative sign next to it, in this case the first and second choice.

however, for the first answer choice it isn't quite part of the formula so we know that the answer choice correctly displays the x value.

to confirm, we can see if the -1 fits correctly with the second answer choice, and as mentioned above a negative number will have a positive sign attached to it. so, for our problem we can see that -1 has been changed to +1, so we can confirm that the second answer choice is correct.

hence, our final answer is y=(x - 1)^2 + 1