Multiply the following binomials; note that every binomial given in the problems below is a polynomial in one variable,
x, with a degree of one. write the answers in standard form, which in this case takes the form ax^2 + + c, where a,
and c are constants.
2. (x + 1)(x − 7)
3. (x + 9)(x + 2)
4. (x − 5)(x − 3)
5. x+ 15 .2 (x − 1)
6. x − 5
4 x − 3

In step-by-step-explanation

Step-by-step explanation:

2)  ( x + 1 ) * ( x - 7 )   =  x² - 7x + x - 7    ⇒  x² - 6x  - 7  

In  x² - 6x  - 7    a = 1   b = -6  c = -7

3) ( x + 9 ) * ( x + 2 )  =  x² + 2x + 9x + 18   ⇒  x² +  11x  + 18

In   x² +  11x  + 18   a  = 1   b  =  11   c  =  18

4) ( x - 5 ) * ( x - 3 )   =  x² - 3x - 5x + 15   ⇒  x²  -  8x  +  15

In   x²  -  8x  +  15     a  =  1    b  =  -8   c  =  15

5) (  x +  15 ) * 2 * ( x  -  1 )  ⇒   (  x +  15 ) * ( 2x - 2 )  ⇒  2x² -2x + 30x - 30

2x²  +  28x  -  30      a  =  2   ² b  =  28    c  =  30

6) ( x - 5 ) * ( 4x  - 3 )    ⇒  4x²  - 3x - 20x + 15

In  4x²  - 3x - 20x + 15      ⇒   a = 4    b  =  -20   c  =  15

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %

twenty-six miles over two gallons because the proportion for the original 13 miles to one gallon would be written 13/1 and, doing the same thing to the top and bottom, i multiplied by 2 and got 26/2