Which set of transformations would prove δqrs ~ δuts? reflect δuts over y = 2, and dilate δu′t′s′ by a scale factor of 2 from point s. reflect δuts over y = 2, and translate δu′t′s′ by the rule (x − 2, y + 0). translate δuts by the rule (x + 0, y + 6), and reflect δu′t′s′ over y = 6. translate δuts by the rule (x − 2, y + 0), and reflect δu′t′s′ over y = 2.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

step-by-step explanation:

x-intercept:

(

−

1

+

√

7

,

0

)

,

(

−

1

−

√

7

,

0

)

y-intercept:

(

0

,

−

6

)

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