What is the least positive integer divisible by the numbers 2, 4, and 7?

Least positive integer divisible by the numbers 2, 4, and 7 is  28

Step-by-step explanation:

We can find the least positive integer divisible by the numbers 2, 4, and 7 by taking the LCM

First lets List all prime factors for each number.

Prime Factorization of 2

2 is prime  =>  

Prime Factorization of 4 is:

2 x 2  =>  

Prime Factorization of 7 is:

7 is prime  =>

For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.

The new superset list is

2, 2, 7

Multiply these factors together to find the LCM.

LCM = 2 x 2 x 7 = 28

1/800 is the right answer

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1