What equation represents the line that is perpendicular to y=1/2x - 3 and passes through the point (4,-6)?

The equation of line perpendicular to given line and passing through point (4 , - 6) is y = - 2 x - 2

Step-by-step explanation:

Given as :

The equation of line is

y = x - 3

Now, standard equation of line is

y = m x + c

where m is the slope of line and c is the y-intercept

So, comparing with standard line equation with given line equation

∴ slope of given line = m =

Again

other line is perpendicular to given line and passes through point (4 , - 6)

Let The slope of other line = M

∵ Two lines are perpendicular

∴ From perpendicular lines property , the product of lines = - 1

i.e m × M = -1

Or,   × M = -1

Or M =

∴  M = - 2

So, The slope of other line = M = - 2

Now, equation of line with slope - 2 and points (4 , - 6) in slope-point form

y - = M (x - )

Or, y - ( - 6) = ( -2) × (x - 4)

Or, y + 6 = - 2 x + 4

Or, y = - 2 x + 4 - 6

∴   y = - 2 x - 2

So, The equation of other line is y = - 2 x - 2

Hence, The equation of line perpendicular to given line and passing through point (4 , - 6) is y = - 2 x - 2  Answer

what is the original number? you forgot to add it.

$655.61 which is option c

step-by-step explanation:

price of house =   $146,000

initial rate = 3.5%

mortgaged paid in this = 3.5 % of $146,000

                                        =

                                        =$5110

the total years would be = 7

total mortgaged paid = 7 * $5110

                                      =$35770

remaining money = $146000-35770

                                =$110230

new mortgaged payment = 5 % of 110230

                                            =  

                                            =$655.61