Solving a right triangle ‼️ (round to the nearest tenth) can someone me find b, a, and c ❓

see explanation

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the 2 angles from 180° for B

B = 180° - (90 + 47)° = 180° - 137° = 43°

Use the tangent and cosine ratios in the right triangle  for a and c

tan47° = =

Multiply both sides by 18

18 × tan47° = a , thus

a ≈ 19.3 ( to the nearest tenth )

cos47° = =

Multiply both sides by c

c × cos47° = 18 ( divide both sides by cos47° )

c = ≈ 26.4 ( to the nearest tenth )