What is the value of 5x³+4y³ when x=4 and y=3

 428

Step-by-step explanation:

This is a substitution problems,

Just substitute for the values of x and y , multiply them out and add.

Here we go;

                5x³  + 4y³

            =  5(4³)  + 4(3³)

            =  5( 4 x 4 x 4 ) + 4( 3 x 3 x 3)

            =  5 x 64 + 4 x 27

            =  320 + 108 add directly or find the common factor

            =  4(80 + 27)

            =  4(107)

            =  4 x 107

            =  428

show da graph

step-by-step explanation:

look at the picture.

1.

ef : ab = 2 : 3

gf : cb = 2 : 3

gh : cd = 2 : 3

he : da = 2 : 3

2.

∠a ≅ ∠e

∠b ≅ ∠f

∠c ≅ ∠g

∠d ≅ ∠h

3.

use pythagorean theorem:

the length of the abcd trapezoid sides:

|ab| = 3 cm

|bc| = 10 cm

|cd| = 3(3) cm = 9 cm

|da| = 8 cm

the perimeter of abcd = 3 + 10 + 9 + 8 = 30 cm

the ratio of perimeters of the tarapezoids is equal 2 : 3.

substitute:

      cross multiply

      divide both sides by 3