An isosceles trapezoid abcd with height 2 units has all its vertices on the parabola y=a(x+1)(x−5). what is the value of a, if points a and d belong to the x−axis and m∠bad=60^o?

a = -0.3575

Step-by-step explanation:

The points A and D lie on the x-axis, this means that they are the x-intercepts of the parabola, and therefore we can find their location.

The points A and B are located where

This gives

Now given the coordinates of A, we are in position to find the coordinates of the point B. Point B must have y coordinate of y=2 (because the base of the trapezoid is at y=0), and the x coordinate of B, looking at the figure, must be x coordinate of A plus horizontal distance between A and B, i.e

Thus the coordinates of B are:

Now this point B lies on the parabola, and therefore it must satisfy the equation  

Thus

Therefore

i dont understand the question? ?

step-by-step explanation: