What is the equation of a line with a slope of four and x intercept of -10

y=4x+40

Step-by-step explanation:

slope equals 4

x-intercept= -10

y=mx+b for the x-intercept the y equals zero so plugging zero the y and -10 to the x

0=4(-10)+b

0=-40+b now you isolate the variables

b=40 so the equation is y=4x+40 because you have the slope you just pluggin the numbers to the equation

drop out of school or go to quizlet, quizlet is better

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)