Aline with slope $\frac 23$ contains the point $p(-18, -12)$. what is the $x$-intercept of the line?

Therefore, the x-intercept of the line is 0

A line with slope 2/3 contains the point P(-18, -12). What is the x intercept of the line?

Step-by-step explanation:

Given;

Slope m = 2/3

Straight line equation is given as

y = mx+c

Where m = slope and c = intercept on y axis

For this case,

y = 2/3x + c 1

At point (-18,-12), Eqn 1 becomes;

-12 = 2/3(-18) + c

-12 = -12 + c

c = 0

The straight line equation becomes

y = 2/3x + 0

Therefore at y = 0 the value of x = 0

Therefore the intercept is at (0,0)

Therefore, the x-intercept of the line is 0

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step-by-step explanation: