What is the slope of a line that is perpendicular to a line whose equation is 5y=10+2x ?

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The slope of a line that is perpendicular to a line whose equation is 5y=10+2x is -5 /2.

The slope intercept form equation is represented as follows:

where

m = slope

b = y-intercept

So, the equation will be express in this format to know the slope of the equation. Therefore,

5y=10+2x

divide through by 5

y = 2 + 2/5 x

y = 2/5 x + 2

The slope of the equation is 2/5.

For a line to be perpendicular to the slope of an equation the product of there slopes will be -1. Therefore,

2/5m₂ = -1

cross multiply

2m₂ = -5

m₂ = -5 / 2

Therefore, the slope of a line that is perpendicular to a line whose equation is 5y=10+2x is -5 /2.

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y = 2 - 5/2x

Step-by-step explanation:

5y = 10 + 2x

y = 2 + 2/5x

Perpendicular line have negative inverted slope to their counterpart. The slope here is 2/5, so invert that and turn it negative and you get a slope of -5/2 for your perpendicular line.

y = 2 - 5/2x

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