How much work must be done on a 6000-kg stone car to increase its speed
from 5 m/s to 10 m/s?

225000J

Step-by-step explanation:

where

W= work done

F=force

S=distance

but F=ma

so we can write the equation

Also,

We put equation (2) and equation (3) into equation (1)

This implies,

From the question

m=6000kg

u=5m/s

v=10m/s

By substitution we obtain