Write an equation of the line with the given characteristics (show all work)

1. points on line: (-1,9), (1,1)

2. vertical line through (-8,6)

1. y = - 4 x + 5

2.  x = -8

Step-by-step explanation:

1.  (-1,9) (1,1)

y = mx + b

m = (y-y') / (x-x') = (1-9) / (1-(-1)) = -8 / 2 = - 4

b = y - mx = 9 - (-4) x (-1) = 5

equation: y = - 4 x + 5

check: (1,1)   y=1 = (-4) x 1 + 5 = 1

2. Vertical line through (-8,6) is a line perpendicular to x axis

    x = -8

8

step-by-step explanation:

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b