If you write all the whole numbers from 1 to 500 in a row, what will be the 500th digit?
a. 0 or 1b. 2 or 3c. 4 or 5d. 6 or 7e. 8 or 9

The 500th digit from 1 to 500 in a row will be;

A: 0 or 1

The double digit numbers are; 10 to 99 = 90 numbers × 2 = 180 digits

This is a total of 180 + 9 = 189 digits

Thus, after 99, we are looking for the;

500 - 189 digit = 311th digit

(100 + x)3 = 312

100 + x = 312/3

100 + x = 104

x = 104 - 100

x = 4

The 104th term after 99 is;

104 + 99 = 203

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As per the question, the 500th digit would be:

a). 0 or 1

To write,

Numbers from

The numbers containing 1 digit digits  (1 to 9)

The numbers containing 2 digits ×   (from 10 to 99)

To find,

digit

Remaining

As we know, 311 can not be divided by 3, and therefore, we will look for the nearest number that is divisible by 3 i.e. 312

So, assuming the x as 100 + nth digit

∵

Now,

∵

Since the term is employed rather than the , it implies that. Thus, 0 would be the digit.

Thus, option a is the correct answer.

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x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17

225x²+4=0

225x²=0-4

225x²=-4

x²=-4/225

x=±√-4/225