The value of the car reduces by 15% every year from 2012.
find the year in which the value of the car will first be below 25% of the price paulo paid in 2010.

2020

Happy New Year!

Step-by-step explanation:

Paulo Received his car in 2010. 2 years later his car started depreciating. Our goal here is to find the year that his car is worth less than 25% of what he actually paid. Let say he paid $7000 for the car multiply that by 0.25 and you 25% of what he paid which is $1750. That is the goal number. So we can take 15% off of 7000 every year starting from 2012.

2012 - $5950

2013 - $5057.50

2014 - $4298

2015 - $3653

2016 - $3105

2017 - $2639

2018 - $2243

2019 - $1907

2020 - $1621

I hope this helps you.

rx and sx

step-by-step explanation:

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,