Ijust need factoring or solving this one

v = 1/2(1 + i√23) ,  1/2(1 - i√23).

Step-by-step explanation:

-2v^2 - v + 12 =  -3v^2 + 6

-2v^2 + 3v^2 - v + 12 - 6 = 0

v^2 - v + 6 = 0

This will not factor so we could use the quadratic formula to solve it:

For the equation ax^2 + bx + c = 0 the roots are:

x = [ - b +/-  sqrt(b^2 - 4ac) ] / 2a.

So here we have:

v = [-(-1) +/- sqrt((-1)^1 - 4*1*6)] /  2

v = [ 1 +/- sqrt (-23)] / 2

= 1/2 +  i√23/2 ,    1/2 -  i√23/2

= 1/2(1 +  i√23) ,  1/2(1 -  i√23).

im pretty sure its

(8,15)

step-by-step explanation:

if im not mistaking its

step-by-step explanation: